$\mathbf{a} = \begin{pmatrix} 3 \\ -2 \end{pmatrix}$ and $\mathbf{b} = \begin{pmatrix} -1 \\ 5 \end{pmatrix}$
(a) Write $2\mathbf{a} + \mathbf{b}$ as a column vector. [1]
(b) Write $\mathbf{a} - 3\mathbf{b}$ as a column vector. [2]
- (a) $\begin{pmatrix} 5 \\ 1 \end{pmatrix}$B1
- (b) $3\mathbf{b} = \begin{pmatrix} -3 \\ 15 \end{pmatrix}$ seen, or one component of the answer correct (6 or $-17$ in the correct position)M1
- (b) $\begin{pmatrix} 6 \\ -17 \end{pmatrix}$ cao (do not accept coordinates $(6, -17)$ for this mark)A1
- Answer: (a) $\begin{pmatrix} 5 \\ 1 \end{pmatrix}$ (b) $\begin{pmatrix} 6 \\ -17 \end{pmatrix}$
- Examiner tip: Subtracting a negative trips people up: the top line is $3 - (-3) = 6$, not 0.