Solve the inequality $|2x-3|<|x+1|$.
- Squares both sides: $(2x-3)^2<(x+1)^2$M1
- $3x^2-14x+8<0$A1
- Factorises $(3x-2)(x-4)<0$M1
- Critical values $x=\tfrac23$ and $x=4$A1
- $\tfrac23
A1 - Answer: $\tfrac23
- Examiner tip: Squaring is valid because both sides are non-negative; check a test value inside and outside the interval.