Let $z=3+4i$ and $w=1-2i$.
(a) Find $zw$. [2]
(b) Find $\dfrac zw$ in the form $a+bi$. [3]
- Expands $(3+4i)(1-2i)=3-6i+4i-8i^2$M1
- $11-2i$A1
- Multiplies numerator and denominator by $1+2i$M1
- $\dfrac{-5+10i}{5}$A1
- $-1+2i$A1
- Answer: (a) $11-2i$ (b) $-1+2i$
- Examiner tip: Replace $i^2$ by $-1$, and multiply by the conjugate of the denominator.