A crane lifts a load of weight 800 N through a vertical height of 12 m in 16 s.
(a) Calculate the work done by the crane on the load. [3]
(b) Calculate the useful power output of the crane. [2]
- (a) work done = force × distance moved (in direction of force) or $W = Fd$(1)
- (a) $W = 800 \times 12$(1)
- (a) 9600 J(1)
- (b) power = work done ÷ time or $P = \dfrac{9600}{16}$ allow ecf from (a)(1)
- (b) 600 W(1)
- Answer: (a) 9600 J (b) 600 W
- Examiner tip: The weight (800 N) is already a force — do not multiply by g again.