Examiner tip: In beta decay the atomic number goes UP by 1 because a neutron changes into a proton.
3Grade 8–95 marks
Uranium-238 ($^{238}_{92}$U) decays through a series of alpha and beta-minus emissions to form the stable isotope lead-206 ($^{206}_{82}$Pb).
(a) Determine the number of alpha particles and the number of beta particles emitted in the series. [4]
(b) Explain why beta-minus decay does not change the mass number of a nucleus. [1]
(a) decrease in mass number = 238 − 206 = 32(1)
(a) number of alpha decays = 32 ÷ 4 = 8(1)
(a) atomic number after 8 alpha decays = 92 − 16 = 76(1)
(a) number of beta decays = 82 − 76 = 6(1)
(b) a neutron changes into a proton (and an electron), so the total number of nucleons (protons + neutrons) is unchanged; allow the beta particle (electron) has a mass number of 0 / is not a nucleon(1)
Answer: 8 alpha and 6 beta; nucleon number unchanged in beta decay
Examiner tip: Do the alphas first: only alpha decay changes the mass number, so it fixes how many alphas there are.
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